Fiber Optics and Total Internal Reflection

fiber

High speed communications have become extremely important to our society. Transferring high quality voice, video, and data at high speeds has become commonplace thanks to physicists. One of the technologies that physicists have developed to transfer data is the use of fiberoptic cables. When using fiberoptic cables we translate data into pulses of light which we then allow to travel through the cable.


Fiberoptic cables are long strands of glass or plastic that allow light to travel through the material without letting it escape from the cable back into the air until they reach the end of the cable. They accomplish this by using the concept of total internal reflection.

Remember the rules of refraction. When light moves from a substance that is more optically dense to one that is less optically dense it speeds up. This is what happens when light moves from glass or plastic into air. When this happens, the angle of refraction gets larger.

Now, if you keep increasing the angle of incidence you will reach a point when the angle of refraction is 90 degrees. This means the light will not be seen on the other side. If you increase the angle of incidence past this point the light will reflect back into the substance. We can then make the light stay inside the fiberoptic cable until it reaches the other end. Look below for a series of pictures that show this.
fiber

refr crit ang total internal reflection
When light moves from glass (more optically dense) to air (less optically dense) The angle of refraction is larger than the angle of incidence.
If you keep increasing the angle of incidence, there is a point at which the angle of refraction will reach 90 degrees. At this point the light will not be seen by an observer on the air side.
If you increase the angle of incidence beyond the critical angle the light can not even skim the surface of the two materials. Instead it will be reflected back into the surface. This is called Total Internal Reflection.

We can find the critical angle øC by setting the angle of refraction q2 to 90o and using Snell's Law:
n1sin øC= n2sin 90o
n1sin øC= n2(1)
n1sin øC= n2

so

crit ang = n2/n1

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